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[ In reference to "Easy Shell Scripting" in LG#133 ]
Papciak, Gerard (Gerry) [Gerard.Papciak at Encompassins.com]
Hello...
I have a number of files in a Unix directory that need certain words replaced.
For instance, for ever file inside /TEST I need the word 'whs' replaced with 'whs2'.
I have search and searched the sed command and kornshell scripting...no luck
Sed 's/whs/whs2/g /TEST*.* > outfileThe above came close but places the contents of all files into one.
Any advice?
-- Gerry Papciak Information Delivery
[[[Elided content]]]
Faber J. Fedor [faber at linuxnj.com]
On 05/06/09 21:37 -0500, Papciak, Gerard (Gerry) wrote:
> Hello... > > I have a number of files in a Unix directory that need certain words > replaced. > > For instance, for ever file inside /TEST I need the word 'whs' replaced > with 'whs2'. > > I have search and searched the sed command and kornshell scripting...no > luck > > > Sed 's/whs/whs2/g /TEST*.* > outfile > The above came close but places the contents of all files into one. > > Any advice?
Try the following:
perl -p -i -e 's/whs/whs2/g' /TEST/*
(google 'perl pie' for details, or just wait for Ben to wake up
-- Regards, Faber Fedor President Linux New Jersey, Inc. 908-320-0357 800-706-0701
Ben Okopnik [ben at linuxgazette.net]
On Fri, Jun 05, 2009 at 09:37:41PM -0500, Papciak, Gerard (Gerry) wrote:
> Hello > > I have a number of files in a Unix directory that need certain words replaced. > > For instance, for ever file inside /TEST I need the word 'whs' replaced with > 'whs2'. > > I have search and searched the sed command and kornshell scripting, no luck > > > Sed s/whs/whs2/g /TEST*.* > outfile > > The above came close but places the contents of all files into one. > > Any advice?
You need the '-i' (in-place edit) option of 'sed':
sed -i 's/\<whs\>/&2/g' *
This will make the replacements within the individual files. Do note the use of '\<whs\>', which means '"whs" as a word' (that being what you asked for) and '&', which means 'string matched by previous regex'.
In the old days, before 'sed' stole that option from Perl , the answer would have been a tiny bit more complex:
for file in * do /usr/bin/sed 's/\<whs\>/&2/g' $file > $file.NEW /bin/mv $file.NEW $file done
-- * Ben Okopnik * Editor-in-Chief, Linux Gazette * https://LinuxGazette.NET *
Ben Okopnik [ben at linuxgazette.net]
[Gerry, please remember to include the list in the CC.]
On Fri, Jun 05, 2009 at 11:03:44PM -0500, Papciak, Gerard (Gerry) wrote:
> OK...you indicated sed -i 's/\<whs\>/&2/g' * > > 1st source of confusion: \<whs\ ....I understand the backslashes can > act as 'delimiters', but why the '<'-sign?They're not delimiters; that would be the forward slashes. '\<word\>' is a construct used to define a stand-alone word rather than a string:
echo 'foobar'|sed 's/\<foo\>/xyz/' # Still 'foobar' echo 'foo bar'|sed 's/\<foo\>/xyz/' # Now, it's 'xyz bar'
> SIMPLER CASE to HELP ME GET THIS... > > fisw1pd2 /export/home/c3782/TEST> sed -i 's/rr/zz/g' * > sed: illegal option -- i
Whoops - you've got an older version of 'sed'.
ben@Jotunheim:~$ sed --version GNU sed version 4.1.5
That's why I sent along the two different examples.
> I have 5 files in a directory: a.dat, b.dat, c.dat, d.dat, e.dat. > > Each contains: larry, gerry, diane, marianne, john, wally in separate > lines. > > I want to make each file look like this: lazzy, gezzy, diane, marianne, > john, wally.
I'll quote myself from my previous email:
> for file in * > do > /usr/bin/sed 's/\<whs\>/&2/g' $file > $file.NEW > /bin/mv $file.NEW $file > done
It would work the same way for the above case:
for file in * do /usr/bin/sed 's/rr/zz/g' $file > $file.NEW /bin/mv $file.NEW $file done
Or, as Faber mentioned, you could use Perl. It's had that '-i' option for a long time now.
perl -i~ -wpe 's/rr/zz/g' *
This will make your desired changes in all the files, saving the originals with a '~' extension. If you don't want the backups, then just leave off the '~'.
-- * Ben Okopnik * Editor-in-Chief, Linux Gazette * https://LinuxGazette.NET *
Papciak, Gerard (Gerry) [Gerard.Papciak at Encompassins.com]
I learned today that I do not have perl scripting available on our Unix Box. We established that our version of 'sed' does not have all the features I need.
WE DO HAVE A WORKING SED COMMAND: sed 's/rr/qq/g' a.dat > out.dat
All that is left is the ability to create a cycling loop that routes all files within a directory through that sed-command. I have .ksh at my disposal. I want to update all files within a directory according to the command constructs...not just one file at a time. Got it??
Thanks all.
-- Gerry Papciak Information Delivery office: 847-667-0535 cell: 847-363-7894
Thomas Adam [thomas.adam22 at gmail.com]
On Thu, 11 Jun 2009 16:16:18 -0500 "Papciak, Gerard (Gerry)" <Gerard.Papciak@Encompassins.com> wrote:
> I learned today that I do not have perl scripting available on our > Unix Box. We established that our version of 'sed' does not have all > the features I need. > > WE DO HAVE A WORKING SED COMMAND: sed 's/rr/qq/g' a.dat > out.dat
You have an ancient installation of... something then.
So you have KSH? Great. What part of:
for i in *; do sed -e 's/rr/qq/g' "$i" > "$i.foo" && \ mv "$i.foo" "$i"; done
... is it which isn't going to work for you?
> All that is left is the ability to create a cycling loop that routes > all files within a directory through that sed-command. I have .ksh at > my disposal. I want to update all files within a directory according > to the command constructs...not just one file at a time. Got it??
"command constructs"? The only way you can do it file-by-file. Since you're going to have some ancient version of find, you can still do:
find /somewhere -type f -print | while read foo; do #sed command here done
But guess what? Other than recusiveness, that's no different to globbing -- so can you be more specific about why a for loop won't what you want?
Oh, and one more thing -- please don't top-post on this list, or any other.
-- Thomas Adam
-- "It was the cruelest game I've ever played and it's played inside my head." -- "Hush The Warmth", Gorky's Zygotic Mynci.